Engineering
Physics
Radiation Pressure due to Photon
Question

A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is 3×108 ms–1. The final momentum of the object is

9.0 × 10–17 kg ms–1

1.0 × 10–17 kg ms–1

3.0 × 10–17 kg ms–1

0.3 × 10–17 kg ms–1         

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Solution

 P=hcλc=mV=Etct=ptc

 =30×103×100×1093×108=1017