A resistor 'R' and 2µF capacitor in series is connected through a switch to 200V direct supply. Across the capacitor is a neon bulb that lights up at 120 V. Calculate the value of R to make the bulb light up 5s after the switch has been closed. (log10 2.5 = 0.4)
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v = 200 (1 – e–t/t)
120 = 200(1 – e–t/t)

t/t = log(2.5) = 0.4
5 = (0.4) × R × 2 × 10–6
= R = 2.7 × 106