A right triangular wooden block of mass M is at rest on a table, as shown in figure. The smaller wooden cubes, both with mass m, initially rests on the two sides of the larger block. As all contact surfaces are frictionless, the smaller cubes start sliding down the larger block while the block remains at rest. What is the normal force from the system to the table?

Engineering

Physics

Contact Force

Newtons Second Law of Motion

Motion of Block on Inclined Surface

Question

A right triangular wooden block of mass M is at rest on a table, as shown in figure. The smaller wooden cubes, both with mass m, initially rests on the two sides of the larger block. As all contact surfaces are frictionless, the smaller cubes start sliding down the larger block while the block remains at rest. What is the normal force from the system to the table?

Mg + mg (sin α + sin β)

Mg + mg (cos α + cos β)

mg + Mg

2 mg + Mg

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N = mg cos α

Ny = Mg cos²α

F_total = mg cos²α + mg cos²β + Mg

cos²α + cos²β = 1 (right triangle)

⇒ F_total = mg + Mg