A rigid bar of mass M is supported symmetrically by three wires each of length ℓ. Those at each end are of copper and the middle one is of iron. The ratio of their diameters, if each is to have the same tension, is equal to

Engineering

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Stress Strain and Hookes Law New

Question

A rigid bar of mass M is supported symmetrically by three wires each of length ℓ. Those at each end are of copper and the middle one is of iron. The ratio of their diameters, if each is to have the same tension, is equal to

Y_copper / Y_iron

$\frac{Y_{iron}^{2}}{Y_{copper}^{2}}$

$\frac{Y_{iron}^{}}{Y_{copper}^{}}$

$\sqrt{\frac{Y_{iron}}{Y_{copper}}}$

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$\frac{Mg}{3 \times \frac{{πd}_{1}^{2}}{4}} = Y_{1} \frac{Δℓ}{ℓ}$
$\frac{Mg}{3 π \times \frac{{πd}_{2}^{2}}{4}} = Y_{2} \frac{Δℓ}{ℓ}$
⟹ Y₁d₁² = Y₂d₂²