A sample of U238 {t1/2 = 4.5 ×109 yrs } is found to contain 23.8 g U238 and 20.6 g Pb206. The age of ore is

Engineering

Chemistry

Kinetics of Radioactive Decay

Question

A sample of U²³⁸ {t_1/2 = 4.5 ×10⁹ yrs } is found to contain 23.8 g U²³⁸ and 20.6 g Pb²⁰⁶. The age of ore is

2.25 ×10⁹ yrs

3.5 × 10⁹ yrs

4.5 × 10⁹ yrs

9 ×10⁹ yrs

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$t = \frac{2 .303}{λ} \log \frac{n_{v} + n_{Pb}}{n_{v}}$ n_v = no. of mole of 238_v

$t = \frac{2 .303}{λ} \ln (\frac{0 .2}{0 .1})$ n_Pb = no.of mole of 206_Pb

t = t_1/2