Engineering
Physics
Errors
Question

A screw gauge gives the following reading when used to measure the diameter of a wire.

        Main scale reading : 0 mm.

        Circular scale reading : 52 divisions

Given that 1 mm on main scale corresponds to 100 divisions of the circular scale. The diameter of wire from the above data is :

0.026 cm

0.052 cm

0.52 cm

0.005 cm

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Solution

Least count of screw gauge =1100mm=0.01mn

Diameter - Divisions on circular scale × least count + main scale reading

=52×1100+0 

= 0.52 mm

diameter = 0.052 cm

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