A simple harmonic motion is represented by :y = 5(sin3π t + cos3πt) cmThe amplitude and time period of the motion are :

Engineering

Physics

Basics of Simple Harmonic Motion

Question

A simple harmonic motion is represented by :

y = 5(sin3π t + $\sqrt{3}$ cos3πt) cm

The amplitude and time period of the motion are :

10 cm, $\frac{3}{2}$ s

5cm, $\frac{2}{3}$ s

5cm, $\frac{3}{2}$ s

10cm, $\frac{2}{3}$ s

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$y = 5 (\sin 3 πt + \sqrt{3} \cos 3 πt) cm$

⇒ y = 10 sin(3πt + φ)

⇒ A = 10 cm

⇒ $T = \frac{2}{3}$ sec