A small Block A is released from the top of an incline at height of h = 512 m. All surfaces are frictionless. The block collides with the ground inelastically but does not stick to it. After collision with the spring, it returns back and collides with the incline inelastically but again does not stick to it. Find the maximum height (in m) from the ground attained by block A when it climbs up the incline.

Engineering

Physics

Collision

Question

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After first collision v₁ = V cos 60°
After second collision v₂ = V₁ cos 60° = $\frac{V}{4}$

$\frac{1}{2} {mv}_{2}^{2} = mgh \Rightarrow h = \frac{h_{0}}{16} = \frac{512}{16} = 32 m$

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