A small block of wood of specific gravity 0.5 is submerged at a depth of 1.2 m in a vessel filled with water. The vessel is accelerated upward with an acceleration of a = g/2. Time taken by block to reach the surface is (g = 10 m/s2)

Engineering

Physics

Statics

Question

A small block of wood of specific gravity 0.5 is submerged at a depth of 1.2 m in a vessel filled with water. The vessel is accelerated upward with an acceleration of a = g/2. Time taken by block to reach the surface is (g = 10 m/s²)

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ρvg_eff – ρvg_eff = ρva_rel
a_rel = g_eff = 3g/2

$t = \frac{2}{5} = 0.4$

$\frac{1.2}{10} = \frac{1}{2} \times 15 \times t^{2}$ .

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