A solution of sodium sulfate contains 92 g of Na+ ions per kilogram of water. The molality of Na+ ions in that solution in mol kg

Engineering

Chemistry

Concentration Terms

Question

A solution of sodium sulfate contains 92 g of Na⁺ ions per kilogram of water. The molality of Na⁺ ions in that solution in mol kg^–1 is:

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Molality of Na⁺ $= (\frac{w}{M} \times \frac{1000}{W}) \times 2$ (Na₂SO₄ contains two Na⁺ ions)

$= [(\frac{92}{23} \times \frac{1000}{1000})] \times 2 = 8$