Engineering
Physics
Dopplers Effect
Question

A stationary source is emitting sound at a fixed frequency f0, which is reflected by two cars approaching the source. The difference between the frequencies of sound reflected from the cars is 1.2% of f0. What is the difference in the speeds of the cars (in km per hour) to the nearest integer? The cars are moving at constant speeds much smaller than the speed of sound which is 330 ms–1.

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Solution

 ρ1=c+v1cv1ρ0

 ρ2=c+v2cv2ρ0

 Δρρ0=(c+v1cv1)(c+v2cv2)=1.2100

 =c2v1v2+cv1cv2(c2v1v2cv1+cv2)(cv1)(cv2)

 =2c(v1v2)c2=1.2100

 =v1v2=1.2100×3302×185

 =1.2×33×181007   km/hr.