Engineering
Physics
Conservation of Energy
Moment of Inertia
Circular Motion in Vertical Plane
Question

A steel rod of length L, density d and cross-sectional area A, is hinged at one end so that it can rotate freely in a vertical plane. The rod is released from a horizontal position. When it becomes vertical, the stress at its midpoint is

13dLg/8

dLg/2

2dLg/5

12dLg/8

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Solution
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mg 12 = 12 × ml23ω2
ω = 3gL
T – m2g = m2ω2 × 3L4
T =  + 38 × 3mg =