A steel rod of length L, density d and cross-sectional area A, is hinged at one end so that it can rotate freely in a vertical plane. The rod is released from a horizontal position. When it becomes vertical, the stress at its midpoint is

Engineering

Physics

Elasticity

Question

13dLg/8

dLg/2

2dLg/5

12dLg/8

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mg $\frac{1}{2}$ = $\frac{1}{2}$ × $\frac{m l^{2}}{3}$ ω²
ω = $\sqrt{\frac{3 g}{L}}$
T – $\frac{m}{2 g}$ = $\frac{m}{2}$ ω² × $\frac{3 L}{4}$
T = + $\frac{3}{8}$ × 3mg =

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