Engineering
Physics
Standing Wave on String
Question

A string of length 1m and mass 5g is fixed at both ends. The tension in the string is 8.0 N. The string is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to:

16.6 cm

20.0 cm

10.0 cm

33.3 cm

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Solution

f=n2ℓTm

On solving, n = 5,

5 loops are formed in 1 m.

∴ Separation between successive nodes=15m=20  cm