A thin flexible wire of length L is connected to two adjacent fixed points and carries a current I in the clockwise direction, as shown in the figure. When the system is put in a uniform magnetic field of strength B going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is

Engineering

Physics

Magnetic Force on a Current Carrying Wire

Question

$\frac{IBL}{4 π}$

$\frac{IBL}{2 π}$

$\frac{IBL}{π}$

IBL

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

$2 Tcos (90 ° - \frac{dθ}{2}) = I (dL) B$

$∴ 2 Tsin (\frac{dθ}{2}) = I (Rdθ) B$

T = IRB 2 $π$ R = L

$= \frac{ILB}{2 π}$

Please subscribe our Youtube channel to unlock this solution.