A train is moving along a straight line with a constant acceleration 'a'. A boy standing in the train throws a ball forward with a speed of 10 m/s, at an angle of 60° to the horizontal. The boy has to move forward by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s2 is :

Engineering

Physics

Physical Quantities

Question

A train is moving along a straight line with a constant acceleration 'a'. A boy standing in the train throws a ball forward with a speed of 10 m/s, at an angle of 60° to the horizontal. The boy has to move forward by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s² is :

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

$T = \frac{2 \times 10 \times \sqrt{3}}{2 \times 10} = \sqrt{3} \sec$

x = 10 cos 60° (T) $= 5 \sqrt{3} m$

In frame of train,

$5 \sqrt{3} = \frac{1}{2} \times a \times {(\sqrt{3})}^{2} + 1 .15$ (a : acceleration of train)

a = 5 m/sec²

Please subscribe our Youtube channel to unlock this solution.