A uniform wooden square board of side ℓ is kept on a frictionless horizontal surface such that its distance from a vertical wall is 2ℓ as shown in figure. A man having mass equal to the board is standing on the corner A of the board. If he moves to the centre O of the board then the distance of the centre of the board from the wall will become

Engineering

Physics

Newtons First Law of Motion

Newtons Second Law of Motion

Center of Mass

Question

A uniform wooden square board of side ℓ is kept on a frictionless horizontal surface such that its distance from a vertical wall is 2ℓ as shown in figure. A man having mass equal to the board is standing on the corner A of the board. If he moves to the centre O of the board then the distance of the centre of the board from the wall will become

$\frac{9 l}{4}$

$\frac{7 l}{4}$

$\frac{(5 \sqrt{2} - 1)}{2 \sqrt{2}} l$

$\frac{(5 \sqrt{2})}{4} l$

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m₁s₁ + m₂s₂ = 0
s₁ + s₂ = 0

$s_{12} = \frac{l}{2} \Rightarrow s_{1} = s_{2} + \frac{l}{2}$

$2 s_{2} = - \frac{l}{2}$

$s_{2} = - \frac{l}{4}$

$x = 2 l - \frac{l}{4} = \frac{7 l}{4}$ .