Engineering
Physics
Electric Potential Energy and Electric Potential
Question

A uniformly charged solid sphere of radius R has potential V0 (measured with respect to ) on its surface. For this sphere the equipotential surfaces with potentials 3V02,5V04,3V04​  ​and  V04 have radius R1, R2, R3 and R4 respectively. Then

2R < R4

R1 0 and (R2 – R1) > (R4 – R3)

R1 = 0 and R2 < (R4 – R3)

R1 = 0 and R2 > (R4 – R3)

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Solution

V0=kQR

Vcentre=3kQ2R=3V02

 ⇒ R1 = 0

5kQ4R=kQ2R3(3R2x2)

R2=R2

R3=4R3

R4 = 4R

R2<8R3&2R<4R