A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphic. If the total pressure at equilibrium is 0.8 atm, the value of K is :

Engineering

Chemistry

Kp and Kc Relation

Question

A vessel at 1000 K contains CO₂ with a pressure of 0.5 atm. Some of the CO₂ is converted into CO on the addition of graphic. If the total pressure at equilibrium is 0.8 atm, the value of K is :

1.8 atm

0.3 atm

0.18 atm

3 atm

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CO₂(g) + C(s) $⇌$ 2CO(g)

0.5 atm 2p

0.5–p 2p

Total pressure = 0.5 – P + 2P = 0.8

$K_{P} = \frac{P_{C O}^{2}}{P_{C O_{2}}} = \frac{{(2 P)}^{2}}{(0.5 - P)} = \frac{{(0.6)}^{2}}{(0.5 - 0.3)}$

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