A wedge should be placed in such a way that dropping an elastic rod, length ℓ = 1m , masses m1 = 0.3 kg and m2 = 0.6 kg attached to the ends, on the wedge the rod should rebound in horizontal position without any angular velocity (see fig.) ? The weight of the rod is 0.6 kg.What is the distance of wedge from m1?

Engineering

Physics

Center of Mass

Question

A wedge should be placed in such a way that dropping an elastic rod, length ℓ = 1m , masses m₁ = 0.3 kg and m₂ = 0.6 kg attached to the ends, on the wedge the rod should rebound in horizontal position without any angular velocity (see fig.) ? The weight of the rod is 0.6 kg.What is the distance of wedge from m₁?

0.4 m

0.5 m

0.6 m

0.3 m

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$x = x_{c} = \frac{m_{1} \times 0 + 0.6 \times 0.5 + 0.6 \times 1}{0.3 + 0.6 + 0.6} = \frac{0.9}{1.5} = 0.6$ .

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