Engineering
Physics
Stress Strain and Hookes Law New
Question
A wire can support a maximum load of W. If the wire is cut in 2 equal parts and joined in parallel, what is the maximum load it can now support is xW. Then the value of x is:
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Solution
When a wire is cut and joined in parallel, the cross-sectional area doubles while length halves. The maximum load depends on the breaking stress (σ), which is constant for the material: σ = F/A.
Original wire: Load W = σ × A.
New parallel combination: Total area = 2A. So maximum load = σ × 2A = 2W.
Final answer: