AB and CD are diameters of a circle, ∠OBD = 50º, then ∠AOC is equal to

Foundation

Mathematics Foundation

Tangent to Circle

Question

40º

70º

50º

80º

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∴ ∠DBA = ∠DCA = 50º
   Now in triangle AOC
   OA = OC
⇒ ∠OAC = ∠OCA = 50º
   then
   ∠AOC = 180º – (50º + 50º)
   = 180º – 100º
   = 80º

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