Among the triatomic molecules / ions, BeCl2, N3–, N2O, NO2+, O3, SCl2, ICl2–, I3– and XeF2 the total number of linear molecule(s) / ion(s) where the hybridization of the central atom does not have contribution form the d-orbital(s) is: [Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]

Engineering

Chemistry

VSEPR Theory

Hybridisation

Question

Among the triatomic molecules / ions, BeCl₂, N₃^–, N₂O, NO₂⁺, O₃, SCl₂, ICl₂^–, I₃^– and XeF₂ the total number of linear molecule(s) / ion(s) where the hybridization of the central atom does not have contribution form the d-orbital(s) is:

[Atomic number: S = 16, Cl = 17, I = 53 and Xe = 54]

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${BeCl}_{2}, N_{3}^{-}, N_{2} O, {NO}_{2}^{+}, O_{3}, {SCl}_{2}, {ICl}_{2}^{-}, I_{3}^{-}, {XeF}_{2}$

BeCl₂ → sp → linear

$N_{3}^{-} \overset{}{\to} sp \overset{}{\to} linear$

N₂O → sp → linear

$\overset{\oplus}{N} O_{2} \overset{}{\to} sp \overset{}{\to} linear$

O₃ → sp² → bent

SCl₂ → sp³ → bent

$I_{3}^{-} \overset{}{\to} {sp}^{3} d \overset{}{\to} linear$

${ICl}_{2}^{-} \overset{}{\to} {sp}^{3} d \overset{}{\to} linear$

XeF₂ → sp³d → linear

So among the following only four (4) has linear shape and no d-orbital is involved in hybridization