Engineering
Physics
Electromagnetic Waves
Question

An electromagnetic wave is represented by the electric field E→=E0n^sin [ωt + (6y−8z)] . Taking unit vectors in x, y and z directions to be i^, j^, k^ , the direction of propagation , is :

s^=3j^ − 4k^5

s^=(−3j^ + 4k^5)

s^=4j^ − 3k^5

s^=−4j^ + 3k^5

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Solution

E→=E0n^sin(ωt+(6y−8z)=E0n^sin(ωt+k→⋅r→))

where  r→=xi^+yj^+zk^  and  k→⋅r→=6y−8z

⇒k→=6j^−8k^

Direction of propagation s^=−k^

=(−3j^+4k^5)