Engineering
Physics
Equation of Continuity
Question

An ideal liquid of density ρ is pushed with velocity v through the central limb of the tube shown in the figure. What force does the liquid exert on the tube ? The cross-sectional areas of the three limbs are equal to A each. Assume stream-line flow.

54ρAv2

98ρAv2

ρAv2

32ρAv2

JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Solution
Verified BY
Verified by Zigyan

Velocity of liquid through inclined limbs = v2
Rate of change of momentum of the liquid = ρAv2 + 2 [ρA(v2)2cos60°] = 54ρAv2

Lock Image

Please subscribe our Youtube channel to unlock this solution.