${\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}+(\mathrm{x}+\frac{\mathrm{y}}{4}){\mathrm{O}}_2\underset{}{\overset{}{\to }}{\mathrm{xCO}}_2+\frac{\mathrm{y}}{2}{\mathrm{H}}_2\mathrm{O}$

$10 10(\mathrm{x}+\frac{\mathrm{y}}{4}) 10\mathrm{x}$

By given data, $10(\mathrm{x}+\frac{\mathrm{y}}{4})=55$        ……………..(1)

                                     10x = 40         ……………..(2)

$\therefore$ x = 4, y = 6 ⇒ C₄H₆