At time t = 0, a battery of 10 V is connected across points A and B in the given circuit. If the capacitors have no charge initially, at what time (in seconds) does the voltage across them become 4 V?
[Take : ln 5 = 1.6, ln 3 = 1.1]

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4 = Q = eV (1 – e–t/RC)
4 = 10
t = 1 × 10–6 × 4 × 10–6 × 0.5 = 2 sec.
