Compute the following a2+b2b2+c2a2+c2a2+b2+2ab2bc-2ac-2ab
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[a2+b2+2abb2+c2+2bca2+c2−2aca2+b2−2ab]
=[(a+b)2(b+c)2(a−c)2(a−b)2]
∵ [(a + b)2 = a2 + b2 + 2ab]