Engineering
Physics
Collision
Angular Momentum and Conservation of Angular Momentum
Question

Consider a uniform rod of mass M = 4m and length ℓ pivoted about its centre. A mass m moving with velocity v making angle θ=π4 to the rod's long axis collides with one end of the rod and sticks to it. The angular speed of the rod-mass system just after the collision is:

372vℓ

47vℓ

37vℓ

327vℓ

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Solution

Loi = Lof

mv2×ℓ2=[4mℓ212+mℓ24]×ω

ω=6v72ℓ=32v7ℓ