Consider an electric field , where E0 is a constant. The flux through the shaded area (as shown in the figure) due to this field is :

Engineering

Physics

Electric Flux and Gauss Law and its Applications

Question

Consider an electric field $\vec{E} = E_{0} \hat{x}$ , where E₀ is a constant. The flux through the shaded area (as shown in the figure) due to this field is :

$\frac{E_{0} a^{2}}{\sqrt{2}}$

E₀a²

$\sqrt{2} E_{0} a^{2}$

2E₀a²

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flux through EHBA

= flux through EHDC

= E₀a²