Consider the following complex ions, P, Q and R.
P = [FeF6]3–, Q = [V(H2O)6]2+ and R = [Fe(H2O)6]2+,
the correct order of the complex ions, according to their spin only magnetic moment values (in B.M.) is:
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(P) [FeF6]–3 Fe+3 d5 configuration with WFL
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unpaired electron = 5
(Q) [V(H2O)6]2+ V+2 d3 configuration
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unpaired electron = 3
(R) [Fe(H2O)6]2+ Fe+2 d6 configuration with WFL
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unpaired electron = 4
Spin only magnetic moment (µ) = B.M. (n = unpaired electron)
So, µ of P > R > Q