Since |lnx| is continuous in (0, ∞)

⇒ f(x) = e^–|lnx| is continuous is (0, ∞)

⇒ So number of points where f(x) is discontinuous, m = 0

$\mathrm{f}\left(\mathrm{x}\right)=\left\{\begin{array}{lc}{\mathrm{e}}^{\mathrm{lnx}};& 0<\mathrm{x}<1\\ {\mathrm{e}}^{-\mathrm{lnx}};& \mathrm{x}\ge 1\end{array}\right.$

f(1– ) = 1, f(1+ ) = – 1 ⇒ So number of points where f(x) is non-differentiable, n = 1

m + n = 0 + 1 = 1