Consider the function, f(x) = | x – 2 | + | x – 5 |, x ∈ R.
Statement 1 : f '(3) = 0
Statement 2 : f is continuous in [2, 5], differentiable in (2, 5) and f(2) = f(5).
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f(x) = | x – 2 | + | x – 5 | , x ∈ R
It is clear that f(x) is continuous in R and
Statement 2 is correct.
Statement 1 is also correct but Statement 2 is not the correct explanation of Statement 1.
