Consider the given plot of enthalpy of the following reaction between A and B.
A + B → C + D
Identify the incorrect statement.

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.
Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA
Ea = (D → C)
= 15 – 0 = 15 kJ mol–1
Ea = (A + B) → C = 15 kJ mol–1
Ea = (A + B) → D = 10 kJ mol–1
Ea = C → (A + B) = 20 kJ mol–1 (high activation enthalpy in the reaction)
Activation enthalpy to form C is 5 kJ mol–1 more than that of form D.