Correct method to prepare Me3C–O–Me in good yield is / are

Engineering

Chemistry

Nucleophilic Substitution

Chemical Properties of Alkyl Halide

Chemical reactions of ether

Question

Correct method to prepare Me₃C–O–Me in good yield is / are

Me₃C–Cl + MeONa $\overset{}{\to}$

Me₃C – ONa + MeCl $\overset{}{\to}$

Me₂C = CH₂ $\underset{MeOH}{\overset{H^{\oplus}}{\to}}$

Me₂C = CH₂ $\underset{(ii) SBH}{\overset{(i) Hg {(OAc)}_{2} + MeOH}{\to}}$

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