Correct order of yield of Hofmann alkene in following reaction will be

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The Hofmann elimination favors the least substituted alkene. The yield order depends on the leaving group ability: larger, less basic anions are better leaving groups, promoting elimination over substitution.
The relative base strength order is F- > Cl- > Br- > I-, meaning iodide is the best leaving group. Therefore, the compound with the iodide leaving group will give the highest alkene yield.
Final Answer: I > Br > Cl > F