(cosec θ – cot θ)2 = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

(cosec θ – cot θ)² = ?

$\frac{1 - cosθ}{1 + cosθ}$

none of these

$\frac{1 + cosθ}{1 - cosθ}$

$\frac{1 + sinθ}{1 - sinθ}$

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(cosec θ – cot θ)² = ${(\frac{1 - \cos θ}{\sin θ})}^{2} = \frac{{(1 - \cos θ)}^{2}}{1 - \cos^{2} θ} = \frac{(1 - \cos θ)}{(1 + \cos θ)}$

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