Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL The molarity of the solution is

Engineering

Chemistry

Intensive Extensive State and Path Function

Question

2.00 M

2.05 M

1.78 M

2.22 M

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$M = \frac{x \times d \times 10}{mol wt} = \frac{10 .7 \times 1 .15 \times 10}{60} = 2 .05 M$ x= percentage by weight

$x = \frac{120}{120 + 1000} \times 100$

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