Engineering
Chemistry
First Law and Various Process
Question

During compression of a spring the work done is 10 kJ and 2 kJ escaped to the surroundings as heat. The change in internal energy, (in kJ) is:

8

–12

–8

12

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Solution

Work done on system = +10 kJ

Heat escaped = – 2kJ

ΔU = q + w

= 10 – 2 = 8 kJ