The reaction shown is the Clemmensen reduction, which reduces a carbonyl group (C=O) to a methylene group (CH₂) using zinc amalgam (Zn-Hg) and concentrated hydrochloric acid (HCl). This reaction is specific for aryl alkyl ketones. The starting compound is a ketone with a benzene ring. The end product will be the hydrocarbon where the C=O is converted to CH₂.

The correct product is the alkane: $C{H}_3-C{H}_2-C{H}_2-C{H}_3$ (butane).

Final Answer: The first option (butane).