Engineering
Mathematics
Standard Ellipse
Question

Equation of the ellipse whose axis are the axis of coordinates and which passes through the point (–3, 1) and has eccentricity \(\sqrt {\frac{2}{5}} \) is :

3x2 + 5y2 – 32 = 0

5x2 + 3y2 – 32 = 0

3x2 + 5y2 – 15 = 0

5x2 + 5y2 – 48 = 0

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Solution

\(\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\)

\(\frac{9}{{{a^2}}} + \frac{1}{{{b^2}}} = 1\)          ….(1)

case – 1                       when a > b

b2 = a2 (1 – e2)

b2 = a2 (1 – 2/5)

5b2 = 3a2                       ….(2)

from (1) & (2)

                          \(\frac{{9 \times 3}}{{5{b^2}}} + \frac{1}{{{b^2}}} = 1 \Rightarrow {b^2} = \frac{{32}}{5}\)    

\                                 \({a^2} = \frac{{32}}{3}\)

\                                 \(\frac{{3{x^2}}}{{32}} + \frac{{5{y^2}}}{{32}} = 1\)   Þ 3x2 + 5y2 – 32 = 0 Ans.

case – 2             when b > a

a2 = b2 (1 – e2)     

                                      \( = \frac{3}{5}{b^2}\)      ….(3)

from (1) & (3)

                            \({a^2} = \frac{{48}}{5},{b^2} = 16\)

                            \(\frac{{5{x^2}}}{{48}} + \frac{{{y^2}}}{{16}} = 1\)

 Þ  5x2 + 3y2 – 48 = 0