Find the coordinates of a point A, where AB is diameter of a circle whose centre is (2,

Engineering

Mathematics

Introduction to Determinants

Question

Find the coordinates of a point A, where AB is diameter of a circle whose centre is (2, – 3) and B is the point (1, 4)

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Center of circle is mid point of Diameter

Let A be (x, y)

⟹ 2 = \frac{x + 1}{2}, - 3 = \frac{y + 4}{2}

⇒ x = 3, y = – 10

So, Coordinates of A are (3, – 10)

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