Find the largest number which divides 438 and 606, leaving remainder 6 in each case.
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The largest number divided 438 and 606 leaving remainder 6 is the largest number divides 432(i.e.438 − 6 = 432) and 600 (i.e.606 − 6 = 600)
HCF of 432 and 600 gives the required number.
To find : HCF of 432 and 600
HCF of 432 and 600 using prime factorization
432 = 24 × 33
600 = 23 × 3 × 52
HCF = = 23 × 3 = 24
therefore , the required number is 24.