Engineering
Physics
Thermodynamics
Question

For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127°C. At 2 atm pressure and at 227°C, the rms speed of the molecules will be :

80 m/s

100 m/s

1005 m/s

805 m/s

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Solution

Vrms=3RTMw

⇒Vrms∝T

Now,v200=500400⇒v200=52

⇒v=1005  m/s