Engineering
Mathematics
Length of Perpendicular
Question

For a point P in the plane, let d1(P) and d2(P) be the distances of the point P from the lines x – y = 0 and   x + y = 0   respectively. The area of the region R consisting of all points P lying in the first quadrant of the plane and satisfying 2 ≤ d1(P) + d2(P) ≤ 4, is :

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Solution

 

 2|hk2|  +  |h+k2|    4

 22    |hk|  +  |h+k|  42

Required area = 14((42)2(22)2)=6  (sq. units)