For a uniformly charged ring of radius R, the electric field on its axis has the largest magnitude at a distance h from its centre. Then value of h is:

Engineering

Physics

Electric Field and Charged Particle in Electric Field

Question

$\frac{R}{\sqrt{2}}$

$R \sqrt{2}$

$\frac{R}{\sqrt{5}}$

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Electric field

$E = \frac{KQx}{{(x^{2} + R^{2})}^{3 / 2}}$

$For maxima \frac{dE}{dx} = 0$

$After solving we get, (x \pm \frac{R}{\sqrt{2}})$