For the reaction, 2H2(g) + 2NO(g) → N2(g) + 2H2O(g); the observed rate expression is, rate = kf[NO]2 [H2]. The rate expression for the reverse reaction is:

Engineering

Chemistry

Opposed or Reversible Elementary Reaction

Order of Reaction and Law of Mass Action

Question

For the reaction, 2H₂(g) + 2NO(g) → N₂(g) + 2H₂O(g);

the observed rate expression is, rate = k_f[NO]₂ [H₂]. The rate expression for the reverse reaction is:

kb[N₂][H₂O]²

kb[N₂][H₂O]

kb[N₂][H₂O]²/[NO]

kb[N₂][H₂O]²/[H₂]

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2H₂(g) + 2NO(g) $⇌$ N₂(g) + 2H₂O(g)

$K_{C} = \frac{k_{f}}{k_{b}} = \frac{[N_{2}] {[H_{2} O]}^{2}}{{[H_{2}]}^{2} {[NO]}^{2}}$

Given for forward reaction, rate = kf[NO]²[H₂]

for reverse reaction rate = kb[N₂][H₂O]²/[H₂]