For the resistance network shown in the figure, choose the correct option(s)

Engineering

Physics

Physical Quantities

Question

I₂ = 2A

I₁ = 3A

the current through PQ is zero

The potential at S is less than that at Q

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By input output symmetry, the current in each of the 2 $Ω$ resistance is the same. Similarly, the current in each of the 4 $Ω$ resistance is the same. So the current in each of the 1 $Ω$ resistance is zero.

So, I₂ = $\frac{12}{6}$ = 2A

I₄ = $\frac{12}{12}$ = 1 A

I₁ = I₂ + I₄ = 3A

Taking potential at negative terminal of the battery to be zero, Potential at S = 4 Volt,

Potential at Q = 8 Volt]

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