Engineering
Mathematics
Conditional Probability
Question

For two events if A and B are independent then prove that A', B' are also independent.

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Solution
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Given A, B are independent then P(A ⋂ B) = P(A)P(B).......(1).
Now 
P(A' ⋂ B') = P{ (A ⋃ B)'} [ Using De Morgan's Law]
or, P(A' ⋂ B') = 1 – P(A ⋃ B)
or, P(A' ⋂ B') = 1 – {P(A) + P(B) – P(A ⋂ B)}
or, P(A' ⋂ B') = 1 – {P(A) + P(B) – P(A)P(B)} [ Using (1)]
or, P(A' ⋂ B') = 1 – P(A) – P(B) + P(A)P(B)
or, P(A' ⋂ B') = (1 – P(A))(1 – P(B))
or, P(A' ⋂ B') = P(A')P(B')
This given A' B' are independent.
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