For two given events A and B, P(A⋂B) is :
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∴ P(AUB) = P(A) + P(B) – P(A⋂B)
on rearranging we get
P(A⋂B) = P(A) + P(B) – P(AUB) which is option C
Also ∵ 0 ≤ P(AUB) ≤ 1
⇒ P(A) + P(B) – 1 ≤ P(A⋂B) ≤ P(A) + P(B)
Hence B and C are also correct
Now if P(A⋂B) = P(A) + P(B) + P(A⋂B)
⇒ P(A) + P(B) = 0
which is not necessary for the events A and B
Hence the correct options are A,B and C
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