For x (0, π) the equation sin x + 2 sin 2x – sin 3x = 3 has
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sin x + 2 sin 2x – sin 3x = 3
⇒ 2 sin 2x – 2 cos 2x sin x = 3
⇒ 2 cos 2x sin x – 2 sin 2x + 1 + 1 + 1 = 0
⇒ 2 cos 2x sin x – 2 sin 2x + (sin2x + cos2x) + (sin22x + cos22x) + 1 = 0
⇒ (1 – sin 2x)2 + (sin x + cos 2x)2 + cos2x = 0, simultaneously all 3 are zero is not possible
No solution